2020-05-18
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1610
这个mysql面试题帮忙看一下吗?

对于这道题,给出的参考答案为:select signup_city_id,date(created_at) 日期,avg(banned) 百分比 from users where created_at between "2013-10-1 10:00:00" and "2013-10-22 17:00:00" group by signup_city_id,date(created_at);






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