在我的界面中,我连续排列了3个常量行,包括项目,数量,重量......等列。当我选择行中的数据并提交表单时,只会将第3行数据插入到数据库中。我希望每个包含数据的行都插入到数据库中。对此有何解决方案?谢谢。
更新::我曾尝试使用PHP数组,下面是更新的代码。但是我已经停留在foreach部分,我想将数据插入数据库。
我的看法:
<tr class="item-details">
<td><span class="rowNumber">1</span></td>
<td class="">
<?php
$options = array(
'' => '~Choose An Item~'
);
foreach ($item as $rows){
$options[$rows->id] = $rows->item_name;
}
$select = array(
'name' => 'item_name[]',
'id' => 'item_name',
'class' => 'form-control'
);
echo form_dropdown('item', $options,set_value('item_name'),$select);
?>
</td>
<td class=""><input type="number" class="item-qty" name="qty[]"/></td>
<td><input type="number" name="weight[]" class="weight" /></td>
<td><input type="text" name="promo_code[]" value=""/></td>
<td><input type="text" name="gp[]" value=""/></td>
<td><input type="text" name="discount[]" value=""/></td>
<td><input type="text" name="unit_price[]" value=""/></td>
<td align="right" class="totalwithouttax">0.00</td>
<td align="right" class="totaltax">0.00</td>
<td align="right" class="totalamtincltax">0.00</td>
</tr><br/>
<tr class="item-details">
<td><span class="rowNumber">2</span></td>
<td class="">
<?php
$options = array(
'' => '~Choose An Item~'
);
foreach ($item as $rows){
$options[$rows->id] = $rows->item_name;
}
$select = array(
'name' => 'item_name[]',
'id' => 'item_name',
'class' => 'form-control'
);
echo form_dropdown('item', $options,set_value('item_name'),$select);
?>
</td>
<td class=""><input type="number" class="item-qty" name="qty[]"/></td>
<td><input type="number" name="weight[]" class="weight" /></td>
<td><input type="text" name="promo_code[]" value=""/></td>
<td><input type="text" name="gp[]" value=""/></td>
<td><input type="text" name="discount[]" value=""/></td>
<td><input type="text" name="unit_price[]" value=""/></td>
<td align="right" class="totalwithouttax">0.00</td>
<td align="right" class="totaltax">0.00</td>
<td align="right" class="totalamtincltax">0.00</td>
</tr><br/>
<tr class="item-details">
<td><span class="rowNumber">3</span></td>
<td class="">
<?php
$options = array(
'' => '~Choose An Item~'
);
foreach ($item as $rows){
$options[$rows->id] = $rows->item_name;
}
$select = array(
'name' => 'item_name[]',
'id' => 'item_name',
'class' => 'form-control'
);
echo form_dropdown('item', $options,set_value('item_name'),$select);
?>
</td>
<td class=""><input type="number" class="item-qty" name="qty[]"/></td>
<td><input type="number" name="weight[]" class="weight" /></td>
<td><input type="text" name="promo_code[]" value=""/></td>
<td><input type="text" name="gp[]" value=""/></td>
<td><input type="text" name="discount[]" value=""/></td>
<td><input type="text" name="unit_price[]" value=""/></td>
<td align="right" class="totalwithouttax">0.00</td>
<td align="right" class="totaltax">0.00</td>
<td align="right" class="totalamtincltax">0.00</td>
解决办法:首先使你的全部3部分HTML表单输入名称数组
<input type="number" class="item-qty" name="qty[]"/>
<input type="number" name="weight" class="weight[]" />
...
然后将数据数组循环为
$qty = $this->input->post('qty', TRUE);
$weight = $this->input->post('weight', TRUE);
$orderItems = array();
for ($i = 0; $i < count($qty); $i++) {
if ($qty[$i]) {
$orderItems[] = array (
'order_id' => $orderHeaderId ,
'product_id' => 7 ,
'item' => 'TEST' ,
'qty' => $qty[$i] ,
'weight' => $weight[$i]
...
);
}
}
现在你可以使用insert_batch方法作为
if ($orderItems) {
$this->db->insert_batch('table_name', $orderItems);
}








暂无数据