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关于问题的背景描述和相关数据的下载见另一个帖子

https://www.cda.cn/discuss/post/details/60273784c58002671ea20afd

下载完csv数据后需要先将数据导入到mysql里面再进行查询

import pandas as pd

import numpy as np

#将csv数据变成数据框

data1=pd.read_csv("D:\\A2021_02_13.csv")

#-----------------------------------------------------------------

# 接下来将数据框导出到mydql数据库中

#---------------------------------------------------------------------------------

#创建python和mysql的连接通道

from sqlalchemy import create_engine

connection1=create_engine("mysql+pymysql://root:12345@localhost:3306/test1?charset=utf8")

#create_engine的用法可以用help(sqlalchemy.engine)看下。

#将数据框data1借助通道倒入到mysql test1数据库的biao1

pd.io.sql.to_sql(data1,"biao1",connection1,schema="test1",if_exists="replace")

下面我们用mysql代码来实现查询计算

涉及到的关键词有 mysql 创建临时表 删除临时表 两个整数字段如何相除

drop temporary table if exists temp0;

create temporary table temp0

select 团长ID,STR_TO_DATE(审核通过日期,'%Y-%m-%d' ) as 审核通过日期1,

datediff(统计日期,审核通过日期) as t,

sum(销量) as 销量1,

max(if(销量>0,1,0)) 是否消费

from biao1

where (STR_TO_DATE(审核通过日期,'%Y-%m-%d' )>=str_to_date("2021-01-01",'%Y-%m-%d')

and STR_TO_DATE(审核通过日期,'%Y-%m-%d' )<=str_to_date("2021-01-24",'%Y-%m-%d')

and datediff(biao1.统计日期,biao1.审核通过日期)>=0

and datediff(统计日期,审核通过日期)<=7)

group by biao1.审核通过日期,biao1.团长ID,biao1.统计日期

order by 审核通过日期,团长ID,t

;

drop temporary table if exists temp1;

create temporary table temp1

select 审核通过日期1,团长ID,

max(case t when 0 then 是否消费 else NULL end) as t0,

max(case t when 1 then 是否消费 else NULL end) as t1,

max(case t when 2 then 是否消费 else NULL end) as t2,

max(case t when 3 then 是否消费 else NULL end) as t3,

max(case t when 4 then 是否消费 else NULL end) as t4,

max(case t when 5 then 是否消费 else NULL end) as t5,

max(case t when 6 then 是否消费 else NULL end) as t6,

max(case t when 7 then 是否消费 else NULL end) as t7

from temp0 group by 团长ID;

drop temporary table if exists temp2;

create temporary table temp2

select temp1.*,1 as count1,

(if((t0+t1)=2,1,0)) as 是否次日留存,

(if((t0+t1+t2+t3+t4+t5+t6)=7,1,0)) as 是否7日留存

from temp1;

drop temporary table if exists temp3;

create temporary table temp3

select sum(count1) as 新注册总人数,

sum(是否次日留存) as 次日留存人数,

sum(是否7日留存) as 7日留存人数

from temp2 group by count1;

select *,

(次日留存人数*1.0/新注册总人数) as 次日留存率,

(7日留存人数*1.0/新注册总人数) as 7日留存率

from temp3;