心盛待花开

2020-12-18   阅读量: 563

mysql两日期之间的工作日(除去周六日,不考虑节假日)

扫码加入数据分析学习群

答:select (floor(days/7)*5+days%7
-case when 6 between wd and wd+days%7-1 then 1 else 0 end
-case when 7 between wd and wd+days%7-1 then 1 else 0 end ) INTO str
from
(select datediff(e,s) as days,weekday(s)+1 as wd) as a;
ELSE

select (-(floor(days/7)*5+days%7
-case when 6 between wd and wd+days%7-1 then 1 else 0 end
-case when 7 between wd and wd+days%7-1 then 1 else 0 end) ) into str
from
(select datediff(s,e) as days,weekday(e)+1 as wd) as a;
end if;
RETURN str;
END
select first_func('2015-11-17','2015-11-20')

添加CDA认证专家【维克多阿涛】,微信号:【cdashijiazhuang】,提供数据分析指导及CDA考试秘籍。已助千人通过CDA数字化人才认证。欢迎交流,共同成长!
44.4254 2 0 关注作者 收藏

评论(0)


暂无数据

推荐课程