Python第三天作业操作答案

vegetable_price = {

'紫贝天葵': {'low':6.50, 'mean':6.75, 'high':7.00},

'金丝南瓜': {'low':7.50, 'mean':7.75, 'high':8.00},

'鱼腥草叶': {'low':8.00, 'mean':8.50, 'high':9.00},

'鱼腥草根':{'low':6.60, 'mean':6.75, 'high':7.00},

'圣女果': {'low':3.50, 'mean':3.75, 'high':4.00},

'荷兰豆': {'low':8.00, 'mean':8.50, 'high':9.00},

'朝天椒': {'low':18.00, 'mean':19.00, 'high':20.00},

'绿菜花': {'low':1.80, 'mean':1.90, 'high':2.00},

'球茎茴香': {'low':7.50, 'mean':7.75, 'high':8.00},

}

题目：

1. 从字典中提取出朝天椒的今日最高价，查找出鱼腥草叶的均价

2. 查找数据中有没有红尖椒存在，如果没有则返回“没有这种菜”，同时在字典中添加这种菜，菜的价格为：5.00, 5.25，5.50，然后打印新的字典；如果有就返回这种菜的全部价格。

3. 弹出鱼腥草叶的数据

4. 求出所有蔬菜最高值的平均值

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操作代码：

1. 从字典中提取出朝天椒的今日最高价，查找出鱼腥草叶的均价

Vegetable_price[‘朝天椒’][‘high’]

Vegetable_price[‘鱼腥草叶’][‘mean’]

或者:

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2. 查找数据中有没有红尖椒存在，如果没有则返回“没有这种菜”，同时在字典中添加这种菜，菜的价格为：5.00, 5.25，5.50，然后打印新的字典；如果有就返回这种菜的全部价格。

if vegetable_price.get('红尖椒', "没有这种菜") == "没有这种菜":

vegetable_price['红尖椒'] = {'low':5.00, 'mean':5.25, 'high':5.50}

print(vegetable_price)

else:

print(vegetable_price.get('红尖椒', "没有这种菜"))

或者:

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3. 弹出鱼腥草叶的数据

vegetable_price.pop("鱼腥草叶")

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4. 求出所有蔬菜最高值的平均值

num = 0

# 求出所有蔬菜最高值的平均值

for key in vegetable_price:

num += vegetable_price[key]['high']

high_mean = num / len(vegetable_price)

high_mean

或者:

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